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(C) Given that the particle starts from rest,initial velocity $u = 0$. The acceleration $a$ is constant.For the first $10\, s$ $(t_1 = 10\, s)$:$s_1 =

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$s_2 = 3s_1$

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(C) Given that the particle starts from rest,initial velocity $u = 0$. The acceleration $a$ is constant.For the first $10\, s$ $(t_1 = 10\, s)$:$s_1 = ut_1 + \frac{1}{2}at_1^2 = 0(10) + \frac{1}{2}a(10)^2 = 50a$.For the total time of $20\, s$ $(t_{total} = 20\, s)$:$s_{total} = s_1 + s_2 = u(t_{total}) + \frac{1}{2}a(t_{total})^2 = 0(20) + \frac{1}{2}a(20)^2 = 200a$.Substituting $s_1 = 50a$ into the total distance equation:$50a + s_2 = 200a$.Therefore,$s_2 = 200a - 50a = 150a$.Comparing $s_1$ and $s_2$:$\frac{s_2}{s_1} = \frac{150a}{50a} = 3$.Thus,$s_2 = 3s_1$.

$A$ particle experiences a constant acceleration for $20\, s$ after starting from rest. If it travels a distance $s_1$ in the first $10\, s$ and a distance $s_2$ in the next $10\, s$,then:

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